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Congratulations to bllyjo, rochrox and andreappd, who each won 50 clams for answering last week's question correctly.
The answer was 364 gifts. Here's a simple way to explain it. Each day you will get a partridge in a pear tree. After the second day, you'll get, along with the partridge, you'll get two turtle doves and so on and so forth. Therefore, you'll have 12 partridges, 22 turtle doves, 30 French hens, 36 calling birds, 40 gold rings, 42 geese a-laying, 42 swans a-swimming, 40 maids a-milking, 36 ladies dancing, 30 lords a-leaping, 22 pipers piping and 12 drummers drumming. If you add all of those up, you'll get 364 as your total number of gifts.
Now for this week's riddle.
When Santa was thinking about last year's Christmas Eve route, he thought that his team of reindeer didn't go as fast as they could. He wished to change the line-up in a way that would get him back at the North Pole faster this year. The sleigh needs exactly eight reindeer to pull Santa and all the gifts. On Christmas Eve night, Rudolph will be in the front. How many ways can Santa rearrange his reindeer while keeping Rudolph in front?
Remember, do not share your answer on the BBS's. When you have the answer, y-mail it to me. The first three people with the correct answer will get an unknown amount of clams (it could change from the last time)!
Check back next week for the answer for this week and a new riddle.
This is bluebag, going to celebrate my friend's birthday . . .
(We're not gonna take it, no, we're not gonna take it, we're not gonna take it anymore . . .)
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